If I have a triangle with angles A,B,and C, and sides a,b,and c, and I know that Angle C is 60degrees and that side b=5; side a=8, what do c, A, and B equal? please help!!
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to find c use the eqn
c^2=a^2+b^2-2ab*cosC
=64+25-80*cos(60)=49
c=7
a/sinA=c/sinC
sinA=a*sinC/c=8*sin60/7=
A=81.79
B=180-A-C=38.21
c^2=a^2+b^2-2ab*cosC
=64+25-80*cos(60)=49
c=7
a/sinA=c/sinC
sinA=a*sinC/c=8*sin60/7=
A=81.79
B=180-A-C=38.21
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(8*sin60)/7
=8*0.866025404/7
=0.989743319
=8*0.866025404/7
=0.989743319
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I showed that in radians as in EXcel angle is in radians. I later converted and gave you the angle in degrees. You wete right
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You have to use either law of sines or law of cosines. I would look both up and see which formula fits the data you have. I don't know it off the top of my head, but If you look it up yourself, you'll see why and learn it better!
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use the formula
c^2 = a^2 + b^2 - 2ab cos C
and
(sinA)/a = (sinB)/b = (sinC)/c
c^2 = a^2 + b^2 - 2ab cos C
and
(sinA)/a = (sinB)/b = (sinC)/c