If someone can solve these three questions for me, and show their work, it would be very appreciated! Thanks soo much (:
Expand and evaluate numerical terms.
1, 100(√xy / 1000)
2. ln(e^19x^20)
Write each expression as a single logarithm;
3. 1/2lnx - 3lny - ln(z-2)
Expand and evaluate numerical terms.
1, 100(√xy / 1000)
2. ln(e^19x^20)
Write each expression as a single logarithm;
3. 1/2lnx - 3lny - ln(z-2)
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1. The notation is a little ambiguous, but assuming it's
= 100 * ( sqrt(xy) / 1000 ) = sqrt(xy)/10
but if it's
= 100 * (sqrt( xy / 1000 )) = sqrt( 100^2 * xy / 1000 ) = sqrt( 10,000 * xy /1000 ) = sqrt(10xy)
2. Again, it could be either
= ln( e^(19 * x^20) ) = 19 * x^20 because ln( e^(x) ) = x
or
= ln( e^( (19x)^20 ) = (19x)^20
3. = ln( x^(1/2) - ln( y^3 ) - ln( z - 2 ) because ln( x^y ) = y ln x
= ln[ (sqrt(x)) / ( y^3 * ( z - 2 ) ] because ln(xy) = ln x + ln y
= 100 * ( sqrt(xy) / 1000 ) = sqrt(xy)/10
but if it's
= 100 * (sqrt( xy / 1000 )) = sqrt( 100^2 * xy / 1000 ) = sqrt( 10,000 * xy /1000 ) = sqrt(10xy)
2. Again, it could be either
= ln( e^(19 * x^20) ) = 19 * x^20 because ln( e^(x) ) = x
or
= ln( e^( (19x)^20 ) = (19x)^20
3. = ln( x^(1/2) - ln( y^3 ) - ln( z - 2 ) because ln( x^y ) = y ln x
= ln[ (sqrt(x)) / ( y^3 * ( z - 2 ) ] because ln(xy) = ln x + ln y
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1. not clear what the sqrt covers
2. 19*lne + 20 lnx = 19 + 20 lnx
3. ln(sqrt(x)/(y^3(z-2))
2. 19*lne + 20 lnx = 19 + 20 lnx
3. ln(sqrt(x)/(y^3(z-2))