The area of a rectangular athletic field is represented by the expression 9z^7-42z^4+72z^2 square meters. Write an algebraic expression to represent one possible set of dimensions (in the sense “length times width”) of the athletic field. Include correct units with your solution.
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9z^7 - 42z^4 + 72z^2
3z^2(3z^5 - 14z^2 + 24)
L = 3z^2 m
W = 3z^5 - 14z^2 + 24 m
3z^2(3z^5 - 14z^2 + 24)
L = 3z^2 m
W = 3z^5 - 14z^2 + 24 m
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To solve this problem, just pick any number to plug in as z. You can use pretty much any number, which is why the question only asks for one possible set of dimensions, implying that there are many right answers.
For example, I picked probably the easiest number: 1. Since 1^x is just 1, you end up with 9 - 42 + 72, which equals 39m², which you can get by having a 3m x 13m field. Kind of a small, oblong field, but it works.
Just for something different, you can use 2 also, and you end up with 1152 - 672 + 288, which equals 768m², which you can get by having a 16m x 48m field.
For example, I picked probably the easiest number: 1. Since 1^x is just 1, you end up with 9 - 42 + 72, which equals 39m², which you can get by having a 3m x 13m field. Kind of a small, oblong field, but it works.
Just for something different, you can use 2 also, and you end up with 1152 - 672 + 288, which equals 768m², which you can get by having a 16m x 48m field.
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Factor out 3z^2 to get
(3z^2)(3z^5-14z^2+24)
all in meters
(3z^2)(3z^5-14z^2+24)
all in meters
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your question is not correct