The diving board at a swimming pool is approximately 48 ft. above the water. the equation: h = -16tsquared + 8t +48 gives a divers approximate height: h, after t: seconds. About how long does it take the diver to enter the water?
About 0.8 sec
About 1.4 sec
About 2 sec
About 2.4 sec
About 0.8 sec
About 1.4 sec
About 2 sec
About 2.4 sec
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h=(-16t^2 + 8t + 48)
h=-8 (2t^2 - t - 6)
Quadratic formula
t= [1 plus/minus 7] / 4
t=2 or -1.5
t=2 since time cant be negative
h=-8 (2t^2 - t - 6)
Quadratic formula
t= [1 plus/minus 7] / 4
t=2 or -1.5
t=2 since time cant be negative
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H = 0 when the diver reaches the water
16t^2 - 8t - 48 = 0
2t^2 - t - 6 = 0
2t^2 - 4t + 3t - 6 = 0
( t - 2) ( 2t + 3) =0
t cannot be minus
thus time taken = 2 seconds
16t^2 - 8t - 48 = 0
2t^2 - t - 6 = 0
2t^2 - 4t + 3t - 6 = 0
( t - 2) ( 2t + 3) =0
t cannot be minus
thus time taken = 2 seconds
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use quqdratic formula
-16t^2+8t+48
2t^2-t-6=0
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t=2
-16t^2+8t+48
2t^2-t-6=0
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t=2
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h = -16t^2 + 8t +48
Since, h = 48 ft. So,
48 = h = -16t^2 + 8t +48
-16t^2 +8t = 0
8t(-2t + 1) = 0, SO,
t = 0, OR, -2t +1 = 0, ===> t = 1/2
t = 1/2 second >=========================< ANSWER
Since, h = 48 ft. So,
48 = h = -16t^2 + 8t +48
-16t^2 +8t = 0
8t(-2t + 1) = 0, SO,
t = 0, OR, -2t +1 = 0, ===> t = 1/2
t = 1/2 second >=========================< ANSWER
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16 t ² - 8 t - 48 = 0
2 t ² - t - 6 = 0
( 2t + 3 ) ( t - 2 ) = 0
t = 2 sec
2 t ² - t - 6 = 0
( 2t + 3 ) ( t - 2 ) = 0
t = 2 sec
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هل هذه خيارات ام مسلسلات ؟
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use the quadratic formula
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Takes too long.