Algebra help!!! what is the square root of x+3= the square root of 3x-6

please explain step by step

√(x + 3) = √(3x - 6); square both sides
√(x + 3)^2 = √(3x - 6)^2; simplify
x + 3 = 3x - 6; subtract 3x from both sides
x - 3x + 3 = 3x - 3x - 6; simplify
-2x + 3 = -6; subtract 3 from both sides
-2x + 3 - 3 = -6 - 3; simplify
-2x = -9; divide both sides by -2
-2x/-2 = -9/-2; solve
x = 9/2 <----------Answer

Blessings

sqrt(x + 3) = sqrt(3x - 6)

Square both sides.

x + 3 = 3x - 6
3 + 6 = 3x - x
9 = 2x
4.5 = x

check: sqrt(4.5 + 3) = sqrt 7.5
............sqrt[3(4.5) - 6] = sqrt 7.5

√(x + 3) = √(3x - 6)

x + 3 = 3x - 6

2x = 9 --> x = 9/2

√(x + 3) = √(3x - 6)
x + 3 = 3x - 6
3x - x = 3 + 6
2x = 9
x = 9/2 = 4.5