The center of a circle is at (7, -3) and it has a radius of 9. What is the equation of the circle
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The center of a circle is at (7, -3) and it has a radius of 9. What is the equation of the circle

[From: ] [author: ] [Date: 11-05-17] [Hit: ]
-3) and has radius 9, the only answer that fits is the second one.(x - 7)² + (y + 3)² = 81-where a is the x coordinate of the center, b is the y coordinate of the center and r is the radius.(x-7)^2 + (y+3)^2 = 81-The basic form ofequation for a circle is (x-h)^2 + (y-k)^2 = r^2where (h,k) is the location of the center and r is the radius so the second one is correct.......
(x - 7)^2 + (y + 3)^2 = 3

(x - 7)^2 + (y + 3)^2 = 81

(x + 7)^2 + (y - 3)^2 = 3

(x + 7)^2 + (y - 3)^2 = 81

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The equation for a circle centered at (h, k) and with radius r is given by:

(x - h)² + (y - k)² = r²

So, if a circle is centered at (7, -3) and has radius 9, the only answer that fits is the second one.

(x - 7)² + (y + 3)² = 81

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where a is the x coordinate of the center, b is the y coordinate of the center and r is the radius. The equation of a circle is (x-a)^2 + (y-b)^2 = r^2

Therefore the equation of this circle is;

(x-7)^2 + (y+3)^2 = 81

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The basic form of equation for a circle is (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the location of the center and r is the radius so the second one is correct.

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The first one is the correct answer

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second one
1
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