Solve this equation BY FACTORING -16n^2-64n+64=0

The multiple choices on the quiz included: a.2 b.-2 c.-4 d.1/2 but none of these work!!! I'm so confused!!!!!!!!!!!!!!!!!

-16n^2 - 64n + 64 = 0
-16(n^2 + 4n - 4) = 0

n^2 + 4n - 4 = 0

you can't factor this equation with integers. It is prime. Either there was a typo on the quiz or on this question.

(-4 ± √32) / 2
(-4 ± 4√2) / 2

x = -2 ± 2√2

Edit @ Atoria & Stephen, let's try your answers....

x = -2

-16 * (-2)^2 - 64 * -2 + 64 = 0
-64 + 128 + 64 = 0
128 = 0
-2 is not a solution

x = 2

-16 * 2^2 - 64 * 2 + 64 = 0
-64 - 128 + 64 = 0
-128 = 0
2 is not a solution

-16n^2-64n+64=0 =>
(-4x - 8)(-4x - 8)=0 =>
The equation equals 0 when (-4x - 8) = 0
-4x = 8
x = -2

A. 2

Follow order of operations.
Parenthesis
Exponents
Multiplication and Division
Addition and Subtraction.

-16n^2 -64n +64=0

-16(n^2+4n+4)=0

n^2+4n+4=0

(x+2)^2=0

x=-2

(4n - 8)^2 = 0
Since a 0 factor gives us a 0 product, set a factor to zero
4n = 8
n = 2
Answer: A

The time you wasted to type this ques. you should try it once to solve..:)