find y'(a) by applying the product rule and (b) by multiplying the factors to produce a sum of simpler terms to differentiate. y=(7-x^2)(x^3-5x+3)
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A). Y' = (7-x^2)*(3x^2-5)+ (x^3-5x+3)(-2x)
= (21x^2-35-3x^4+5x^2)+ (-2x^4+10x^2-6x)
= -5x^4+36x^2-6x-35
B) y= 7x^3-35x+21-x^5+5x^3-3x^2
= -x^5+12x^3-3x^2-35x+21
Y'= -5x^4+36x^2-6x-35
Hoping this helps!
= (21x^2-35-3x^4+5x^2)+ (-2x^4+10x^2-6x)
= -5x^4+36x^2-6x-35
B) y= 7x^3-35x+21-x^5+5x^3-3x^2
= -x^5+12x^3-3x^2-35x+21
Y'= -5x^4+36x^2-6x-35
Hoping this helps!