How would I do this: 19 * the square root of 3/ 2? Im really confused..
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Assume that the expression is 19√(3/2).
Set each term with √ to get:
19√(3)/√(2)
Then, multiply the top and bottom by √2 to rationalize the denominator:
19√(3)/√(2) * √2/√2
= 19√(6)/√4
= 19√(6)/2
I hope this helps!
Set each term with √ to get:
19√(3)/√(2)
Then, multiply the top and bottom by √2 to rationalize the denominator:
19√(3)/√(2) * √2/√2
= 19√(6)/√4
= 19√(6)/2
I hope this helps!