A pn junction diode has parameters , I(s) = 10^(-10) A and n = 2. Find the diode current at room temperature if the applied diode voltage is 0.6.
The general equation to find diode current is : I(d) = I(s)(e^(Vd/(n)vT) - 1)
How can I solve this problem if the turn on voltage (vT) is not given? Not only that, the question doesn't indicate whether the pn junction is reverse or forward bias?
Can someone please shed some light on this question.
The general equation to find diode current is : I(d) = I(s)(e^(Vd/(n)vT) - 1)
How can I solve this problem if the turn on voltage (vT) is not given? Not only that, the question doesn't indicate whether the pn junction is reverse or forward bias?
Can someone please shed some light on this question.
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Vt is about .026 volts at 25 degrees C and a positive value for Vd means the diode is forward biased. This page has more information. http://en.wikipedia.org/wiki/Diode