A 5 gallon container holds 35 grams of nitrogen (formula: N2, molecular weight = 28 grams per mole) at a temperature of 400 kelvin. What is the container pressure in units of kilopascals?
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For this question you need to use the ideal gas law, PV=nRT. Since we are solving for pressure, P=nRT/V.
There are about 3.79 liters in a gallon, so our V=5*3.79
There are 101.325kPa in one atmosphere.
Our amount of moles is 35/28
And our ideal gas constant is .0821 for this question.
So we have P*101.325=35*.0821*400/28*5*3.79
Solve for P and we get P=35*.0821*400/28*5*3.79*101.325, which is equal to 2.14*10^-2 kPa.
There are about 3.79 liters in a gallon, so our V=5*3.79
There are 101.325kPa in one atmosphere.
Our amount of moles is 35/28
And our ideal gas constant is .0821 for this question.
So we have P*101.325=35*.0821*400/28*5*3.79
Solve for P and we get P=35*.0821*400/28*5*3.79*101.325, which is equal to 2.14*10^-2 kPa.
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