20ml solution HCl 0.1 M with 10ml solution HCl 0.22 M.
-
mol HCl in 20mL of 0.1M solution = 20/1000*0.1 = 0.002 moles
mol HCl in 10mL of 0.22M solution = 10/1000*0.22 = 0.0022 mol
You have 0.002+0.0022 =0.0042 mol HCl in 30mL solution
Molarity = 0.0042/0.030 = 0.14M solution HCl
This dissociates completely , therefore
[H+] 0.14M
[Cl-] = 0.14M
mol HCl in 10mL of 0.22M solution = 10/1000*0.22 = 0.0022 mol
You have 0.002+0.0022 =0.0042 mol HCl in 30mL solution
Molarity = 0.0042/0.030 = 0.14M solution HCl
This dissociates completely , therefore
[H+] 0.14M
[Cl-] = 0.14M
-
so 20ml solution HCl 0.1 M mix with with 10ml solution HCl 0.22 M. ok,
let V1= 20 mL , M1= 0.1 M , V2= 10 mL , and M2= 0.22 M
M(total) = (M1*V1 + M2*V2)/(V1+V2) = (20*0.1 + 0.22*10)/(20+10) = 1.4 M
so, concentration of HCl now is 1.4 M,
HCl ---> H+ + Cl-
[H+] = 1.4 M , [Cl-]= 1.4 M
got it?
let V1= 20 mL , M1= 0.1 M , V2= 10 mL , and M2= 0.22 M
M(total) = (M1*V1 + M2*V2)/(V1+V2) = (20*0.1 + 0.22*10)/(20+10) = 1.4 M
so, concentration of HCl now is 1.4 M,
HCl ---> H+ + Cl-
[H+] = 1.4 M , [Cl-]= 1.4 M
got it?