Help with AP Chemistry Question

Soda-lime glass is prepared by fusing sodium carbonate, Na2CO3; lime-stone, CaCO3; and sand, SiO2. The composition of the glass varies, but the commonly accepted reaction for its formation is

Na2CO3+CaCO3+6SiO2------> Na2CaSi6O14+ 2CO2

Using this equation, how many kilograms of sand would be required to produce enough glass to make five thousand 400-g wine bottles?

THANKSNNN :)

Assuming the reaction has run to completion,
You'll be using the mole ratio

So say you have 5,000 x 400g wine bottles
that will be 2,000,000 g worth of Na2CaSi6O14, soda-lime glass

Find moles of the glass:
2,000,000g x 1mol Na2CaSi6O14/ 478.56g = 4179.2 moles
Since SiO2 has a mole ratio of 6 to 1 with glass, for
every mole of soda-lime glass there will be 6 moles of SiO2, or 'sand'

So, 4179.2 moles x 6 = 25075 moles SiO2 needed
Convert moles SiO2 to grams:
Molar mass SiO2: 60.08 g/mol
25075mol x 60.08g/mol = 1506520 grams SiO2, or 1,507 kg