A volume of 25ml of H2CrO4 is titrated to an end point using 5.37ml of 0.50 N NaOH. Assuming complete neutrali

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A volume of 25ml of H2CrO4 is titrated to an end point using 5.37ml of 0.50 N NaOH. Assuming complete neutrali

[From: ] [author: ] [Date: 12-05-23] [Hit: ]

50= 0.1/2 x 0.002685 moles=0.0.00134 moles H2CrO4/0.025L= o.......

A volume of 25ml of H2CrO4 is titrated to an end point using 5.37ml of 0.50 N NaOH. Assuming complete neutralization, calculate the molarity of the H2CrO4

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2 NaOH + H2CrO4 -----> Na2CrO4 + 2 H2O
2 moles NaOH react with 1 mole H2CrO4

moles NaOH: 0.00537 L x .50= 0.002685 moles
1/2 x 0.002685 moles=0.00134 moles H2CrO4
0.00134 moles H2CrO4/0.025L= o.054 M H2CrO4

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