Gasohol is a mixture of ethanol and gasoline. Balance the equation and determine the mass of CO2 from the combustion of 100.0 g ethanol.
___C2H5OH(I) + ___O2(2) --> ___CO2(g) + ___H2O(g)
___C2H5OH(I) + ___O2(2) --> ___CO2(g) + ___H2O(g)
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C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(g)
(100.0 g C2H5OH) / (46.0687 g C2H5OH/mol) x (2/1) x (44.0096 g CO2/mol) =
191.1 g CO2
(100.0 g C2H5OH) / (46.0687 g C2H5OH/mol) x (2/1) x (44.0096 g CO2/mol) =
191.1 g CO2