x+6<5
I subtracted X to get it into slope intercept form ( I have to graph it on an actual graph with a dashed
or solid line and shaded on either side & I need to test it ) I also change the inequality sign to an = sign because it doesn't really matter right now.
So now I have 6=-X+5
What would the Slope be? Would it be -1 or just 1? Why!
M=?
B ( Y intercept )=5
I subtracted X to get it into slope intercept form ( I have to graph it on an actual graph with a dashed
or solid line and shaded on either side & I need to test it ) I also change the inequality sign to an = sign because it doesn't really matter right now.
So now I have 6=-X+5
What would the Slope be? Would it be -1 or just 1? Why!
M=?
B ( Y intercept )=5
-
If the inequality is really just
x+6 < 5
there is no "slope" and no "intercept," because there is no "y"
If you MUST do this in an x-y plane, then draw a vertical line at x = -1,
and darken everything to the left of that line.
But you would be justified in representing this in just one dimension
(i.e., just on the x-axis).
x+6 < 5
there is no "slope" and no "intercept," because there is no "y"
If you MUST do this in an x-y plane, then draw a vertical line at x = -1,
and darken everything to the left of that line.
But you would be justified in representing this in just one dimension
(i.e., just on the x-axis).