How to solve for cotθ
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How to solve for cotθ

[From: ] [author: ] [Date: 12-01-05] [Hit: ]
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If sin θ = -1/5 and 270°≤ θ ≤ 360°, the cot θ =? I tried using cos^2θ +sin^2θ= 1, but it didn't work and I didn't use the range of degrees part at all, so I'm confused about how to go about this.

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csc(t)^2 - cot(t)^2 = 1

csc(t) = 1 / sin(t)

(-5)^2 - cot(t)^2 = 1
25 - cot(t)^2 = 1
24 = cot(t)^2
cot(t) = +/- 2 * sqrt(6)

We're in Q4, so cot(t) is negative

cot(t) = -2 * sqrt(6)
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