How do you change 4 and 14/6 into a mixed proper number

I just asked kinda the same question except this one is confusing for me

It is just called a mixed number.
And the answer to your question is to ask yourself, how many times does 6 divide evenly into 14? Then ask how much remains?
So,
6x2=12
14-12=2
so 6 divides into 14 twice evenly, leaving 2 as the remainder.
Now you add the 2 wholes to 4 so, 2+4=6, then the fraction becomes the remainder which was 2 over the original denomiator(bottom number in the fraction) which was 6
so the answer is 6 and 2/6

there is no such thing as a mixed proper number. there is either a mixed number, which is a whole number with a fraction, like 2 1/2, or there is improper fractions, which is when the numerator is higher than the denominator, like 14/3. if you mean improper fraction, all you have to do is multiply the whole number (4) by the denominator (6) and get 24, and then add it to 14 and put it over 6 again. so the answer would be 38/6, which would simplify to 19/3. if you meant to turn it into a mixed number, then you can see that 14/6 is an improper fraction and that 6 can go into 14 two more times, and so you take 12 (6x2) out of the fraction, and that leaves 2/6 (or 1/3), and then you can add 2 to 4, so your answer is 6 1/3

4 14/6

4 7/3

4 + 2 1/3

6 + 1/3

6 1/3.......ANSWER


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