How many watts are there in a volt at 32 ohms

I want to figure out how many watts the headphone jack gives out on the second generation IPod Touch for a school project. I want to know if i have enough watts to power a few christmas light bulbs and still get clear music at the end of the line that i will attach to a small speaker.

Power = (E^2)/R = (1Volt)^2 / 32 = 1/32 = 0.0313 watts. Simply square the voltage and divide by the resistance to get DC Power level.

The question you are also trying to answer depends more on the impedance and frequency of the driving voltage set to the headphones. Adding Christmas light bulbs will change the impedance (combination of resistance and reactance, reactance is caused by the inductance and capacitance in the circuit) and will change the amount of power transferred from the iPAD to the headphones.

Easiest to experiment and measure the results.

hope this helps,

Newton1Law

Equation 1 - Amperage (A) = Voltage (V) divided by Resistance (ohms)
Equation 2 - Wattage (W) = Voltage (V) x Amperage (A)

We can work out the amperage from equation 1:
A = V/R
A = 31.25mA

We can now calculate the wattage:
W = VA
W = 1*0.03125
W = 31.25mW

Your question is not very clear, but power is voltage squared divided by resistance.

It has about half watt output.
To do what you plan to do could overload the AF power amplifier, result could be harmed to your expensive iPod .

Avoid dabbling with volts. It can endanger your life. Why not start getting to know from basics??

I=V/R
watt = I²R=V²/R=1/32=31.25mW