i am trying to find the limit of (tanx/sinx) as x approaches 0 . i already know that it is 1 but i need to find it algabraically. can i get the algabra steps to getting the same outcome That way?
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lim[x→0] tanx / sinx
= lim[x→0] (sinx/cosx) / sinx
= lim[x→0] 1/cosx
= 1/cos0
= 1
Mαthmφm
= lim[x→0] (sinx/cosx) / sinx
= lim[x→0] 1/cosx
= 1/cos0
= 1
Mαthmφm
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You ever heard tanx = sin x/ cos x? Apparently not.