Predict the moles of ammonia that can be made using 22.4 g of nitrogen and an unlimited amount of hydrogen.
Can someone explain this step by step for me...
Can someone explain this step by step for me...
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okay well you should always start by writing a balanced equation
N2 + 3H2 --> 2NH3
Now.. you know that nitrogen is the limiting reactant and hydrogen is in excess so you'll be using a nitrogen to ammonia ratio to find your answer. First, find the moles of nitrogen
n = m/ MM
n = 22.4g / 28 g/mol
n = 0.80 mol
Now that you have the moles of nitrogen, you can set up a N2: NH3 ratio using the coefficients in your balanced equation
0.80 mol/ 1 mol = x/ 2 mol
2mol (0.8mol/1mol) = x
1.6 mol = x
Therefore, you can make 1.6 mol of ammonia using 22.4 g of nitrogen
N2 + 3H2 --> 2NH3
Now.. you know that nitrogen is the limiting reactant and hydrogen is in excess so you'll be using a nitrogen to ammonia ratio to find your answer. First, find the moles of nitrogen
n = m/ MM
n = 22.4g / 28 g/mol
n = 0.80 mol
Now that you have the moles of nitrogen, you can set up a N2: NH3 ratio using the coefficients in your balanced equation
0.80 mol/ 1 mol = x/ 2 mol
2mol (0.8mol/1mol) = x
1.6 mol = x
Therefore, you can make 1.6 mol of ammonia using 22.4 g of nitrogen