I am having issues with part C. I have included the formulas I came up with for part c. Please help.
You recently started the paperwork to purchase your new home, and were just notified that you can move into the house in 2 weeks. You decide to hire a moving company, but are unsure which company to choose. You search online and are interested in contacting two companies, Heavy Lifting and Quick Move, to discuss their rates. Heavy Lifting charges a $75 fee plus $50 per hour. Quick Move charges $100 for the 1st hour and $60 for each additional hour.
c. For what values h (hours) does Quick Move offer the better deal? Express your answer as an inequality. Explain how you reached your answer.
Here's what I have so far.
Heavy Lifting is 75+50h
Quick Move is 100+60h
c.) 100+60h < 75+50h
-100 -100
60h < -25+50h
-50h -50h
10h < -25
10h/10 < -25/10
h < -2.5
Where did I go wrong? Please help!
You recently started the paperwork to purchase your new home, and were just notified that you can move into the house in 2 weeks. You decide to hire a moving company, but are unsure which company to choose. You search online and are interested in contacting two companies, Heavy Lifting and Quick Move, to discuss their rates. Heavy Lifting charges a $75 fee plus $50 per hour. Quick Move charges $100 for the 1st hour and $60 for each additional hour.
c. For what values h (hours) does Quick Move offer the better deal? Express your answer as an inequality. Explain how you reached your answer.
Here's what I have so far.
Heavy Lifting is 75+50h
Quick Move is 100+60h
c.) 100+60h < 75+50h
-100 -100
60h < -25+50h
-50h -50h
10h < -25
10h/10 < -25/10
h < -2.5
Where did I go wrong? Please help!
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You solved the equation just fine. So why the negative value? Because, there are no real time situations where Quick Move offers the better deal. It would be necessary to have an alternate reality where time could be negative (maybe possible on Star Trek, but not for us!)
Put in any positive value you want for h and Heavy Lifting will always have the lower value.
Another way to show this: graph both lines with hours as x and cost as y. The two lines intersect when x is -2.5. All y values to the right of x=-2.5 will have a lower y for Heavy Lifting.
Put in any positive value you want for h and Heavy Lifting will always have the lower value.
Another way to show this: graph both lines with hours as x and cost as y. The two lines intersect when x is -2.5. All y values to the right of x=-2.5 will have a lower y for Heavy Lifting.