How to find the angle between two curves
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How to find the angle between two curves

[From: ] [author: ] [Date: 11-11-21] [Hit: ]
1.x = 0,Lets try it at x = 0.The angle between the y axis and y = -2x would be 30 degrees. Put em together and thats 75 degrees.-I think you differentiate to solve for your slope at a particular point and then use that slope to find a tangent line you are told to use any point so I would use something simple like (0,......
How do i find the angle between two curves f(x) = x^2 - 2x + 5 and g(x) = - 1/2x ^2 + x + 5 at any point of intersection ?

Is there an formula? Do i differentiate each equation and find MT? HELP PLEASE !

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x^2 - 2x + 5 = - 1/2x^2 + x + 5
1.5x^2 - 3x = 0
1.5x(x - 2) = 0
x = 0, x =2

Let's try it at x = 0.
The slope of f(x) at 0 is
f'(0) = 2(0) - 2 = -2

The slope of g(x) at 0 is
g'(0) = -(0) + 1 = 1

Now we need to find the angle between the lines y = -2x and y = x
The angle between the y axis and y = x would be 45 degrees
The angle between the y axis and y = -2x would be 30 degrees. Put 'em together and that's 75 degrees.

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I think you differentiate to solve for your slope at a particular point and then use that slope to find a tangent line you are told to use any point so I would use something simple like (0,0) once you have your tangent equations use each to find your two vectors. Once you have your two vectors you can use the equation cos(theta)=[n(1)(dot)n(2)]/the magnitude of n(1)*n(2) and that should be your angle

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Differentiate the equations to determine the slopes m1 and m2 of the tangent lines. The tangent of the angle x between the two lines is

tanx = (m2-m1)/(1+m1m2)
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