A 10.0 kg object is accelerated horizontally from rest to a velocity of 11.0 m/s in 5.00 seconds by a horizontal force. How much work is done on this object? Please show all your work.
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Work = Force x Distance
Force = Mass x Acceleration
Acceleration = dv/dt
Now plug in all your variables, creating a function for time.
W(t) = .....
and solve for W(5)
Edit:
from "rest" implies that v(0) = 0 m/s, and v(5) = 11 m/s
Find kinematic equation that has relationship with V(initial) and V(final).
Force = Mass x Acceleration
Acceleration = dv/dt
Now plug in all your variables, creating a function for time.
W(t) = .....
and solve for W(5)
Edit:
from "rest" implies that v(0) = 0 m/s, and v(5) = 11 m/s
Find kinematic equation that has relationship with V(initial) and V(final).
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Work done = change in kinetic energy
=> work done = (1/2) * 10 * (11)^2 = 605 J
(Note: Time is irrelavant here.)
=> work done = (1/2) * 10 * (11)^2 = 605 J
(Note: Time is irrelavant here.)