Chemistry - Moles Question - 10 Points

Copper sulfate solution reacts with sodium chromate solution to form a dark red insoluble compound. The equation for the reaction is as follows.

CuSO4(aq) + Na2CrO4(aq) = CuCrO4(s) + Na2SO4(aq)

a) What is the name of this type of reaction?

b) Write an ionic equation for this reaction.

c) When an excess of sodium chromate solution was reacted with 10 cm3 of 1M copper sulphate, 1.2 g of copper chromate was obtained using an experimental procedure. Ar values; Cu=64, Cr=52, O=16

i) Calculate the % yield of copper chromate extracted.

ii) Give three basic steps needed to produce a sample of copper chromate from this reaction.

Please only answer if you know your stuff, as otherwise people will think I've got a proper answer and then I'm stuck struggling. Thanks.

a) double replacement
b) Cu+2 + CrO4-2 -------------------> CuCrO4(s)

c)
CuSO4(aq) + Na2CrO4(aq) = CuCrO4(s) + Na2SO4(aq)
v = 10 mL 1.2 g
C = 1.0 mol/L

Step 1. Calculate moles of CuSO4 mol = 1.0 mol/L x 10 mL =10 millimoles

Step 2. Observe mol ratio between CuSO4 and CuCrO4. It is 1 to 1. Therefore 10 millimoles of CuCrO4 will form

Step 3. Convert 10 millimoles CuCrO4 into mass

mass = mol x Molar mass

10 millimoles x 179.55 g/mol = 1705.5 milligrams or 1.706 g

That is the theoretical yield. You obtained 1.2 g, therefore the percent yield is:

i) 1.2 / 1.7 alll x 100 = 71%

ii) I don't understand the question. Just mix the reactants. Prepare them first I suppose.