In your experiment you determined that 0.3413 grams of oxygen were produced. How many grams of potassium chlorate solid must have been present initially? Give your answer to three decimal places.
Please I need help with this question!!!
Please I need help with this question!!!
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First write the equation then balance
2KClO3---> 2KCl + 3O2
.3416gO2/32gO2 = .0107moles of O2 are produced
The mole of O2 to KClO3 are 3 to 2
There was .0071moles of KClO3
moles =grams/molecular mass
.0071= x/122.5g
x=.87g KClO3
2KClO3---> 2KCl + 3O2
.3416gO2/32gO2 = .0107moles of O2 are produced
The mole of O2 to KClO3 are 3 to 2
There was .0071moles of KClO3
moles =grams/molecular mass
.0071= x/122.5g
x=.87g KClO3