Chemistry calorimeter question!!
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Chemistry calorimeter question!!

[From: ] [author: ] [Date: 11-11-09] [Hit: ]
5 degree Celsius. 14.82 g of water with temperature at 68.4 degree Celsius is poured in, and stirred. The final temperature of all components is 40.......
Given the following information, calculate the heat capacity of the calorimeter in the unit of J/ degree Celsius: A calorimeter contains 19.16 g of water, both temperatures are at 22.5 degree Celsius. 14.82 g of water with temperature at 68.4 degree Celsius is poured in, and stirred. The final temperature of all components is 40.1 degree Celsius.

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heat lost by hot water = mass x c x ∆T
heat = 14.82g x 4.184J/g-ºC x 28.3ºC = 1754.79J

1754.79J = ∆Tcold x (mass water x specific heat water + heat capcity cal)
1754.79J = 17.6ºC x (19.16g x 4.184J-gºC + Ccal)
1754.79J = 1410.91J + 17.6xC
343.87 / 17.6 = C
19.54J/ºC
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