I am trying to answer this question: a) If you were mixing 0.1 M NaOH (aq) and 0.1 M FeCl3 (aq) what would be the correct ration of drops to form the most precipitate?
b) Would the use of phenolphthalein be an appropriate test in this case?
b) Would the use of phenolphthalein be an appropriate test in this case?
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The reaction which would occur is:
3NaOH(aq) + Fe(III)Cl3(aq) --> 3NaCl(aq) + Fe(III)(OH)3(s)
Since the ratio of the reactants NaOH and FeCl3 is 3:1, you should have 3 drops of NaOH solution per one drop of FeCl3 solution, since both reactant solutions have the same molarity.
Yes phenolphthalein would be an appropriate test as it would turn from red-violet to clear if there isnt an excess of NaOH solution.
3NaOH(aq) + Fe(III)Cl3(aq) --> 3NaCl(aq) + Fe(III)(OH)3(s)
Since the ratio of the reactants NaOH and FeCl3 is 3:1, you should have 3 drops of NaOH solution per one drop of FeCl3 solution, since both reactant solutions have the same molarity.
Yes phenolphthalein would be an appropriate test as it would turn from red-violet to clear if there isnt an excess of NaOH solution.