Hiya!
This question reads:
A particle of mass 0.40 kg is moving with velocity v = (5.0i + 6.0j) m/s.
(a) Find the angular momentum L relative to the origin when the particle is at r = (2.0j + 3.0k) m.
I'm meant to answer in terms of i, j, and k.
My understanding is that L = v * r * m
So that would give me m * (v x r), so I do the cross product:
[5 6 0]
[0 2 3]
I tried to find i, which would be 6 * 3 - 0 * 2 = 18 * .4 = 7.2, however this is not correct.
What am I doing wrong?
Thanks!
This question reads:
A particle of mass 0.40 kg is moving with velocity v = (5.0i + 6.0j) m/s.
(a) Find the angular momentum L relative to the origin when the particle is at r = (2.0j + 3.0k) m.
I'm meant to answer in terms of i, j, and k.
My understanding is that L = v * r * m
So that would give me m * (v x r), so I do the cross product:
[5 6 0]
[0 2 3]
I tried to find i, which would be 6 * 3 - 0 * 2 = 18 * .4 = 7.2, however this is not correct.
What am I doing wrong?
Thanks!
-
L = (r x p) = m*( r x v)
Note: You got the order backwards, its r x v, and not v x r.
[i j k]
[0 2 3]
[5 6 0]
Lx = .4 ( 2*0 - 3*6) = -7.2 kg m^2/s
Note: You got the order backwards, its r x v, and not v x r.
[i j k]
[0 2 3]
[5 6 0]
Lx = .4 ( 2*0 - 3*6) = -7.2 kg m^2/s