A 700 g weight is held on a steel cable and spun in a vertical circle. If the cable can withstand a tension of 4100 N, at what velocity will the cable break. (Hint the tension is not the same throughout the period of rotation?
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.7 kg * 9.8 m/s/s = 6.86 N
So cable could break @ 4100 - 6.86 = 4093.14 N
F = MA , 4093 / .7 = 5848 m/s/s required to exceed limit
a = V^2 / R, Since R is not specified , assume R = 1 meter
Then Velocity = SQRT5848 = 76.5 m/s
So cable could break @ 4100 - 6.86 = 4093.14 N
F = MA , 4093 / .7 = 5848 m/s/s required to exceed limit
a = V^2 / R, Since R is not specified , assume R = 1 meter
Then Velocity = SQRT5848 = 76.5 m/s