The length of a poster is 10cm longer than its width. If the area of the poster is
1200cm squared, what is the width of the poster.
1200cm squared, what is the width of the poster.
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let breadth be x
then length = 10 + x
area = l * b
1200 = x * x+10
1200 = x^2 + 10x
0= x^2 + 10x - 1200
0= x^2 + 40x - 30x -1200
0= x(x+40) - 30 (x+40)
0= (x-30)(x+40)
x=30 or x=-40
we take x=30 because breadth cannot be negative
breadth= 30cm
length=40cm
then length = 10 + x
area = l * b
1200 = x * x+10
1200 = x^2 + 10x
0= x^2 + 10x - 1200
0= x^2 + 40x - 30x -1200
0= x(x+40) - 30 (x+40)
0= (x-30)(x+40)
x=30 or x=-40
we take x=30 because breadth cannot be negative
breadth= 30cm
length=40cm
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let x be the width of the poster, then x+10 is the length.
to get the area you multiply length times width, so:
x(x+10)=1200
x^2+10x-1200=0
to get the area you multiply length times width, so:
x(x+10)=1200
x^2+10x-1200=0
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Let width = x
=> length = x+10
1200 = x(x+10) (Length X Width)
1200 = x^2 + 10x
x^2 + 10x - 1200 = 0
=> length = x+10
1200 = x(x+10) (Length X Width)
1200 = x^2 + 10x
x^2 + 10x - 1200 = 0