find the equation of the circle with the endpoints of the diameter (9,-3) and (13,15)
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The center of the circle is the midpoint of diameter : ((9+13)/2, (-3+15)/2) = (11, 6)
And the radius squared, r^2 = (9-11)^2 + (-3-6)^2 = 85
So, the equation is: (x-11)^2 + (y-6)^2 = 85
And the radius squared, r^2 = (9-11)^2 + (-3-6)^2 = 85
So, the equation is: (x-11)^2 + (y-6)^2 = 85