A wooden box weighing 224 N is pushed across the floor by a workman who exerts a horizontal force of 121 N.

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A wooden box weighing 224 N is pushed across the floor by a workman who exerts a horizontal force of 121 N.

[From: ] [author: ] [Date: 13-03-06] [Hit: ]

857) = 4.287m/sec^2.......

If the force of friction between the box and the floor is 23 N, what is the acceleration (in meters/second^2) of the box?

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Net force = mass * acceleration

The box has two forces which affect its acceleration. The force exerted by the workman causes the box to accelerate. The friction force causes the box to decelerate.
Net force = 121 – 23 = 98 N
Mass = weight ÷ 9.8 = 224 ÷ 9.8
98 = (224 ÷ 9.8) * a
Solve for a

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Acceleration = net force/mass.
Net force = (121 - 23) = 98N.
Mass = (224/9.8) = 22.857kg.
Acceleration = (98/22.857) = 4.287m/sec^2.

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