A solution is prepared by mixing 1.00g of Ethanol, C2H5OH, with 100g of water. Calculate the mass percent of ethanol in this solution.
My teacher told me the answer is .99%. However, I have no idea how she got that answer. Someone please show me how my teacher got that answer. I'm really confused.
My teacher told me the answer is .99%. However, I have no idea how she got that answer. Someone please show me how my teacher got that answer. I'm really confused.
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The total mass is 100+1 = 101
mass percent is like all percents, part/wholex100
So 1g/101g x 100 = 0.99%
mass percent is like all percents, part/wholex100
So 1g/101g x 100 = 0.99%
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1 gram ethanol / (101 grams total solution
= 0.0099 = 0.99%
= 0.0099 = 0.99%