Lim as x approaches 0= (sin(x) + e^(x) -1)/(cos(x+(pi/2)))
The answers is apparently -2, but how do you get to that?
The answers is apparently -2, but how do you get to that?
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l'hospital
(cos(x)+ e^(x))/(-sin(x+(pi/2))
then plug in the limit
(cos(0)+e^0)/(-sin(0+pi/2))
= (1+1)/(-1) = -2
(cos(x)+ e^(x))/(-sin(x+(pi/2))
then plug in the limit
(cos(0)+e^0)/(-sin(0+pi/2))
= (1+1)/(-1) = -2
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When x-->0
Derivative of numerator = cos(x)+e^x = 2
Derivative of denominator = -sin(x+pi/2) = -1
By L'Hopital's rule
Lim = 2/-1 = -2
Derivative of numerator = cos(x)+e^x = 2
Derivative of denominator = -sin(x+pi/2) = -1
By L'Hopital's rule
Lim = 2/-1 = -2