A child in danger of drowning in a river is being carried downstream by a current that has speed of 2.50km/h.

A child in danger of drowning in a river is being carried downstream by a
current that has a speed of 2.50 km/h. The child is 0.6 km from shore and 0.8
km upstream of a boat landing when a rescue boat sets out.
a. If the boat proceeds at its maximum speed of 20.0km/h relative to the
water, what heading relative to the shore should the pilot take?(Ans:
36.9 degrees)
b. What angle does the boat velocity make with the shore? (Ans: 41.6 degrees)
c. How long does it take the boat to reach the child? (Ans: 3 mins)

Please help me solve this! thanks!

I will give you some clues. You need to start by setting up a right angled triangle. The base will be 0.6km and the vertical will be 0.8km. You can now use trig to find the hypotenuse and the angle. Draw the shore as a straight vertical line next to your triangle (on the right hand side). The angle between your triangle and the shore is the heading (i.e. 90 degrees minus the angle of your triangle). You should be able to answer the next question with this info. For the last question you need the equation time = distance / speed. The hypotenuse you calculated will be the distance and the speed of the boat is given. Don't forget the distance will be in km and speed is given in km/hr so you will need to convert these units into meters and meters per second. The answer you will get will be in seconds which you need to then convert to minutes (divide by 60). If you follow these steps you will get the exact answers you have given in the brackets.

Just save the child for pete's sake!