An arrow, starting from rest, leaves the bow with a speed of 27.2 m/s. If the average force exerted on the arr
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An arrow, starting from rest, leaves the bow with a speed of 27.2 m/s. If the average force exerted on the arr

[From: ] [author: ] [Date: 12-05-23] [Hit: ]
-It will not be 4 times as fast.Work and energy are the same thing right?Work is force times distance, and the distance is constant.So 4 times more force means 4 times more work.4 times more work means 4 times more energy for the arrow.......
An arrow, starting from rest, leaves the bow with a speed of 27.2 m/s. If the average force exerted on the arrow by the bow was increased 4 times and the arrow was accelerated over the same distance, then with what speed would the arrow leave the bow?

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It will not be 4 times as fast.

Work and energy are the same thing right? Work is force times distance, and the distance is constant. So 4 times more force means 4 times more work. 4 times more work means 4 times more energy for the arrow.

KE=(1/2)m*v^2. So if energy is increased by a factor of 4, then velocity is increased by a factor of 2.

So your final answer is 27.2 m/s * 2 = 54.4 m/s

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4 times faster than it originally did?
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