What is the speed of the block when it is at a position xi/2 = 2.90 cm
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What is the speed of the block when it is at a position xi/2 = 2.90 cm

[From: ] [author: ] [Date: 12-04-25] [Hit: ]
Using the formula above,V = 22.776*(0.058)*sin60° = 1.......
A horizontal spring attached to a wall has a force constant of k = 830 N/m. A block of mass m = 1.60 kg is attached to the spring and rests on a frictionless, horizontal surface as in the figure below.

C) What is the speed of the block when it is at a position xi/2 = 2.90 cm?

I already got part A and B, but I can't seem to get part C. Any help is appreciated.

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w = √(k/m) = 22.776 rad/sec

Assuming xi means the initial deflection of the mass, it also is equal to the amplitude A of the motion:

V = w*A*sinΘ

When x = A/2, Θ = 60°. Using the formula above,

V = 22.776*(0.058)*sin60° = 1.144 m/s
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