PHYSICS INDUCTANCE HELP!
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PHYSICS INDUCTANCE HELP!

[From: ] [author: ] [Date: 12-04-18] [Hit: ]
At what time (in ms) is the emf across the inductor equal to the potential difference across the resistor?Figure: http://edugen.wileyplus.Since this is a series ckt,IL = Vs/R *(1-e^-1213t)Let Vs be the voltage supply.At t=0 VR =0,......
Switch S in Fig. 30-61 is closed at time t = 0 s, initiating the buildup of current in the 12.2 mH inductor and the 14.8 Ω resistor. At what time (in ms) is the emf across the inductor equal to the potential difference across the resistor?

Figure: http://edugen.wileyplus.com/edugen/cours…

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Link doesn't show a diagram btw

First find the L/R time constant: R/L = 1213

Rt/L = 1213t

Since this is a series ckt, the current is the same in R and L

IL = Vs/R *(1-e^-1213t) Let Vs be the voltage supply.

VR = IL*R = Vs(1-e^-1213t) = Vs-Vs*e^-1213t

At t=0 VR =0, at t approaching infinity VR = Vs

VL = LdIL/dt = Vs*e^-1213t

At t=0 VL = Vs, at t approaching infinity VL=0

Set VL = VR

Vs[2*e^-1213t = Vs

e^-1213t =1/2

t = [-1/1213]*ln(1/2) = 0.57ms
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