Determine the volume in milliliters of .10 M Pb(NO3)2 that will fully react with 75.0 mL of .20 M of NaI in solution.
Calculate the volume in liters of .75 M Ca(NO3)2 solution that is required to completely react with 148.2 grams of Na2CO3 according to the following equation:
Ca(NO3)2+Na2CO3=CaCO3+2NaNO3
The molar mass for NaCO3 is 105.99.
You can do either one i just really need help in these.
Thank you!
Calculate the volume in liters of .75 M Ca(NO3)2 solution that is required to completely react with 148.2 grams of Na2CO3 according to the following equation:
Ca(NO3)2+Na2CO3=CaCO3+2NaNO3
The molar mass for NaCO3 is 105.99.
You can do either one i just really need help in these.
Thank you!
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a) What is Nal ?
Never mind , as (NO3) reacts with Na to form NaNO3 , the reaction is a one to one ratio.
A 0.1 m solution of Pb(NO3)2 will contain 0.1 *2 * (NO3) moles per litre
also a 0.2 m solution of Nal will contain 0.2 * 1 * Na moles per litre
so as they react in a 1:1 ratio the volume of Pb(NO3)2 will also be 75 ml.
B)
I think you mean the molar mass of Na2CO3= 105.99
Note this is a 1:1 molar ratio
Then 148.2/105.99 = 1.398245 moles of Na2CO3
So 1.398245/0.75 = 1.864326 Litres
Never mind , as (NO3) reacts with Na to form NaNO3 , the reaction is a one to one ratio.
A 0.1 m solution of Pb(NO3)2 will contain 0.1 *2 * (NO3) moles per litre
also a 0.2 m solution of Nal will contain 0.2 * 1 * Na moles per litre
so as they react in a 1:1 ratio the volume of Pb(NO3)2 will also be 75 ml.
B)
I think you mean the molar mass of Na2CO3= 105.99
Note this is a 1:1 molar ratio
Then 148.2/105.99 = 1.398245 moles of Na2CO3
So 1.398245/0.75 = 1.864326 Litres
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Thank you Extreme that helped me alot (=
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You'd need 75.0 mL of .10 M Pb(NO3)2.
And then 1.864 L of Ca(No3)2.
When you're doing stoichiometry, you normally have to show work, and it's incredibly difficult to type =/
This might help for future problems:
Molarity (M) = moles/Liter (mol/L)
1 Liter (L) = 1000 milliliters (mL)
molar mass = grams/mole (g/mol) (this value is a ratio that will be constant for any substance)
Remember, when doing stoichiometry, to convert units, you have to remove whatever unit you don't want by multiplying it by the inverse. For example, to change molar mass to grams when you know the number of moles, you'd multiply the molar mass by the number of moles.
And then 1.864 L of Ca(No3)2.
When you're doing stoichiometry, you normally have to show work, and it's incredibly difficult to type =/
This might help for future problems:
Molarity (M) = moles/Liter (mol/L)
1 Liter (L) = 1000 milliliters (mL)
molar mass = grams/mole (g/mol) (this value is a ratio that will be constant for any substance)
Remember, when doing stoichiometry, to convert units, you have to remove whatever unit you don't want by multiplying it by the inverse. For example, to change molar mass to grams when you know the number of moles, you'd multiply the molar mass by the number of moles.