Help with logarithm!

I've been given this log and im not sure where to start!

Log5 6.37

If you could show the workings step by step, i'd be very grateful!

I use _ to indicate base

So convert it all into log_ 10

log_5 (6.37) = log_10 (6.37) / log_10 (5) = 1.15

As with all maths problems, its a good idea to check your results backwards

5 ^ 1.1505 = 6.37...

And its always good to do a sanity check if you're not sure.
log5 5 = 1
log5 25 = log5 5^2 = 2

so log5 of 6.something is going to be just a bit more than 1 because 6.something is a bit more than 5 but not as much as 25.

Use a change of base formula loga (x) = ln(x)/ln(a)

log5 (6.37) = ln(6.37)/ln(5) which is about 1.1505

Let log be log to base 5:-
x = log 6.37
5^x = 6.37
x log 5 = log 6.37
x = log 6.37 / log 5
x = 1.15