This problem has to do with the Empire State building ...
Height is 1250ft
h(t) = 1250-16t
Height = 0 at the ground
The question is :
Find the derivative at the given times:
a) t=8.84
b) t=6
Thank you for your help & have a blessed day :)
Height is 1250ft
h(t) = 1250-16t
Height = 0 at the ground
The question is :
Find the derivative at the given times:
a) t=8.84
b) t=6
Thank you for your help & have a blessed day :)
-
Are you sure you have written the expression for h(t) correctly?
The derivative of h(t) = 1250 - 16t is
dh/dt = -16 ft/s which is constant no matter what value 't' has.
But your question (a) and (b) implies that d(h)/dt at 8.84 sec is different from dh/dt at 6 sec.
Perhaps therefore h(t) should read h(t) = 1250 - 16(t^2)
In such a scenario dh/dt = -32*t
Thus at t = 8.84 sec dh/dt = -32*8.84 = -282.88 ft/sec
and at t = 6 sec dh/dt = -32*6 = -192 ft/sec.
And by the way (as you can see) the second derivative is equal to -32 ft/sec/sec acceleration which of course is equal to -32 ft/sec/sec = g the acceleration due to gravity.
The derivative of h(t) = 1250 - 16t is
dh/dt = -16 ft/s which is constant no matter what value 't' has.
But your question (a) and (b) implies that d(h)/dt at 8.84 sec is different from dh/dt at 6 sec.
Perhaps therefore h(t) should read h(t) = 1250 - 16(t^2)
In such a scenario dh/dt = -32*t
Thus at t = 8.84 sec dh/dt = -32*8.84 = -282.88 ft/sec
and at t = 6 sec dh/dt = -32*6 = -192 ft/sec.
And by the way (as you can see) the second derivative is equal to -32 ft/sec/sec acceleration which of course is equal to -32 ft/sec/sec = g the acceleration due to gravity.