Two identically charged objects are 6.2 nm apart. If the electrostatic force between them is 53.9 pN, what is the charge on the objects? Ans. 4.8 x 10-19 C
How do I get that answer?
How do I get that answer?
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Let Q1 and Q2 be the charge on each object, the
the force between two objects is defined by:
F = (k * Q1 * Q2) / ( r^2)
since the two objects have the same charge, Q, then
F = ( k * (Q^2) ) / ( r^2)
Where,
F = 53.9 * 10^-12 N
r = 6.2 * 10^-9 m
k = 8.99 * 10^9 (N m^2)/(C^2)
then,
Q =
square root of (
(53.9*10^-12) * (6.2*10^-9) * (6.2*10^-9)
over,
( 8.99*10^9)
) = 4.8*10^-19
the force between two objects is defined by:
F = (k * Q1 * Q2) / ( r^2)
since the two objects have the same charge, Q, then
F = ( k * (Q^2) ) / ( r^2)
Where,
F = 53.9 * 10^-12 N
r = 6.2 * 10^-9 m
k = 8.99 * 10^9 (N m^2)/(C^2)
then,
Q =
square root of (
(53.9*10^-12) * (6.2*10^-9) * (6.2*10^-9)
over,
( 8.99*10^9)
) = 4.8*10^-19