A 300 g block with an initial speed of 1.5 m/s slides along a horizontal tabletop against a friction force of 2 N. a. How far will it slide before stopping? b. What is the coefficient of friction between the block and the tabletop?
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a = -2/0.3 = -6. 67m/s²
v² = u² +2as
0 = 1.5²-2*6. 67s
s =0.17 m
μ =a /g =-6. 67/ 9.8 =0.68
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v² = u² +2as
0 = 1.5²-2*6. 67s
s =0.17 m
μ =a /g =-6. 67/ 9.8 =0.68
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