Need help finding the area of a rectangle

The length of a rectangle is 3in. more than twice the width. The area is 20sq in. What are the dimensions of the rectangle?

l = length
w = width
l = 2w + 3

Area = l * w = (2w+3) (w) = 20
2w^2 + 3w = 20
2w^2 + 3w - 20 = 0
(2w-5)(w+4) = 0
w+4=0 would mean w=-4 which make no sense so we take the other possibility

2w-5=0
2w=5
w=5/2
l=2w+3=2(5/2)+3=8

dimensions of rectangle is 5/2in by 8in.

Try using algebra. You know the width and the height and the area. The area is width times height.

the length is 3 inches, so the width is (20/3) inches... so the dimesnsions are 3x6.6 in.