Find the magnitude and direction of the current in the figure below, where R = 6.50 and = 10.0 V.
Here's a link to the circuit diagram: http://www.webassign.net/walker/21-34alt.gif
I know it's basic stuff, but I'm having a hard time. Could someone explain this? I'd be very appreciative. thank you!
Here's a link to the circuit diagram: http://www.webassign.net/walker/21-34alt.gif
I know it's basic stuff, but I'm having a hard time. Could someone explain this? I'd be very appreciative. thank you!
-
Total voltage = 25V.
"Internal resistance" of battery = 6.5 ohms.
Total circuit resistance = (6.5 + 6.22 + 15.1) = 27.82 ohms.
Current = (25/27.82) = 0.899A.
Direction of current flow = clockwise (conventional) or anticlockwise (electron flow)
"Internal resistance" of battery = 6.5 ohms.
Total circuit resistance = (6.5 + 6.22 + 15.1) = 27.82 ohms.
Current = (25/27.82) = 0.899A.
Direction of current flow = clockwise (conventional) or anticlockwise (electron flow)
-
V = I*R
I = V/R= 10.0/6.50 ohms = 1.54 amperes
I = V/R= 10.0/6.50 ohms = 1.54 amperes
-
Guruswamy?