Calculus problem. Finding a power series representation for a function

I have to find a power series representation for;

f(x) = ln(x^3 + 9)

Any idea on how to do this? I believe it is something to do with the derivative but I'm not sure where to go from there.

for power series, you need to somehow get the function in the form of 1/(1 - x), and it's usually by either differentiation or integration.

y = ln(x^3 + 9)
y' = 3x^2 / (x^3 + 9)

y' = 3x^2 * 1/(9 + x^3) = 3x^2 * (1/9) 1/(1 + x^3/9) = (1/3)x^2 * 1/[1 - (-x^3/9)]

(1/3)x^2 * ∑{0,inf} (-x^3/9)^n

(1/3)x^2 * ∑{0,inf} (-1)^n * x^(3n) / 3^(2n)

multiply (1/3)x^2 back in,
∑{0,inf} x^(3n+2) / 3^(2n+1)

integrate to return to the original function,
C + ∑{0,inf} (-1)^n * x^(3n+3)/(3n+3) * 1/3^(2n+1)

Edit:
I forgot to say that, to determine C, plug 0 in for x, so:
ln(9 + 0^3) = C
ln(9) = C

so final answer:
ln(9) + ∑{0,inf} (-1)^n * x^(3n+3)/(3n+3) * 1/3^(2n+1)