Calculus: The product and quotient rules

Suppose that f(2) = -3, g(2) = 4, f'(2) = -2, and g'(2) = 7. Find h'(2).

a. h(x) = 5f(x) - 4g(x)
b. h(x) = f(x)g(x)
c. h(x) = f(x) / g(x)
d. h(x) = g(x) / (1+f(x))

Please show your work so i know how it was done. Thanks for your help!!

a. h'(x)= 5f'(x) - 4g'(x) regular differentiation
h'(2)= 5*-2 - 4*7 substituting
= -10 - 28
= -38
b. h'(x)= f(x)*g'(x) + f'(x)*g(x) by product rule
h'(2)= -3*7 + -2*4 substituting
= -21 - 8
= -29
c. h'(x)= (f'(x)*g(x) - g'(x)*f(x)) / (g(x))^2 by quotient rule
h'(2)= (-2*4 - 7*-3)/4^2 substituting
= (-8 + 21)/16
= 13/16
d. h'(x)= (g'(x)f(x) - f'(x)*g(x)) / (1+f(x))^2 by quotient rule
h(2)= (7*-3 - -2*4)/(1 - 3)^2 substituting
= (-21 + 8)/(-2)^2
= -13/4