A certain force F1 gives an object an acceleration of 6 � 106 m/s2. Another force F2 gives the same object an acceleration of 15 � 106 m/s2. What is the acceleration of the object if (a) the two forces act together on the object in the same direction; (b) the two forces act in opposite directions on the object; (c) the two forces act on the object at 90o to each other?
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(a) The two forces act together on the object in the same direction;
The acceleration is algebraic sum of the two accelerations
= 6e6 + 15e6 = 21e6 m/s ²
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(b) The two forces act in opposite directions on the object;
Considering that the right side is positive and 15e6 is in the positive direction 6e6 is in the opposite direction
The resultant acceleration is 15e6 – 6e6 = 9e6 m/s² toward right.
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(c) the two forces act on the object at 90o to each other?
Resultant is 1e6* √ (15² + 6²) = 16.16 m/s²
tan α = 15/ 6
α = 68.2° from the acceleration 6e6 .
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The acceleration is algebraic sum of the two accelerations
= 6e6 + 15e6 = 21e6 m/s ²
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(b) The two forces act in opposite directions on the object;
Considering that the right side is positive and 15e6 is in the positive direction 6e6 is in the opposite direction
The resultant acceleration is 15e6 – 6e6 = 9e6 m/s² toward right.
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(c) the two forces act on the object at 90o to each other?
Resultant is 1e6* √ (15² + 6²) = 16.16 m/s²
tan α = 15/ 6
α = 68.2° from the acceleration 6e6 .
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