Please help me Algebra 1!

1. Find the product.

2m²(5m² -6+2) = ?



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2. Find the area of a rectangle whose length x + 6 and width is 4x.






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Please help me thanks sooo much! ☺

2m^2(5m^2 -4) = 10m^4 - 8m^2 = 2m^2(5m^2 -4)

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(x + 6)*4x = 4x^2 + 24x = 4x(x + 6)

1. You just need to distribute: 2m²(5m² -6+2) = 10m^4 - 12m² + 4m² = 10m^4 - 8m²

2. A = lw
A = 4x(x + 6) = 4x² + 24. Again, you need to distribute. First substitute the values of the length and width. Multiply the two values to get your final answer.

2m^2(5m^2-6+2)
2m^2(5m^2-4)
10m^4-8m^2

4x(x+6)
4x^2+24x